121k^2-4=0

Solution for 121k^2-4=0 equation:

121k^2-4=0

a = 121; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·121·(-4)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*121}=\frac{-44}{242}
=-2/11
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*121}=\frac{44}{242}
=2/11
$